Reactions Involved: 4AgNO3 + H3PO2 + 2H2O → 4Ag + H3PO4 + 4HNO3 2HgCl2 + H3PO2 + 2H2O → 2Hg + H3PO4 + 4HCl
PCl5 reacts with silver to form white silver salt(AgCl). Which than dissolves on adding excess aqueous NH3 to form a soluble complex Reaction Involved: PCl5 + 2Ag → 2AgCl(white ppt.) + PCl3 AgCl +...
White phosphorus 1. It is soft waxy solid having garlic order 2. It is poisonous 3. Has low melting point and boiling point because P4 molecules are held together by weak van der Waal forces of...
Reaction Involved: P4O10 + 4HNO3 → 4HPO3 + 2N2O5 White phosphorous is very reactive as compared to red phosphorous due to angular strain in white phosphorous.
Three oxoacids of nitrogen: 1.Nitric acid(HNO3) 2.Nitrous acid (HNO2) 3.Hyponitrous acid (H2N2O1) + 3 oxidation is shown by HNO2, Therefore it undergoes disproportion reaction, Calculation:...
Calculation: P4O6 + 6H2O → 4H3PO3 4H3PO3 + 8NaOH → Na2HPO3 + 8H20 P4O6 + 8NaOH → 4Na2HPO3 + 2H2O Moles of P4O6 = 1.1/220 = 0.5 Acid formed by one mole of P4o6 requires = 8 mol Acid formed by 0.005...
Calculation: When white phosphorous reacts with chlorine: P4 + 6Cl2 → 4PCl3 PCl3 + 3H2O → H3PO3 + 4HCl ]*4 P4 +6Cl2 +12H2O → 4H3PO3 +12HCl Moles of white P= 62/124 = 0.5mol 1mol of white P4 produces...
Example Reactions: 1. 4Zn +10HNO3(dil) → 4Zn(NO3)2 + NH4NO3 + 3H2O 2. 4Zn +10HNO3(dil) → 4Zn(NO3)2 + N2O + 5H2O 3. 4Zn +4HNO3(conc.) → Zn(NO3)2 + NO2 + 2H2O
Ozone is less thermodynamically stable because it decomposes into oxygen and this decay leads to heat release, so its entropy is positive whereas the free energy is negative for this ozone.
As the decrease in the electronegativity of the halogen, the tendency of the XO3 group (X = halogens) to withdraw the electrons of the O-H bond has decreased so the perhalic acid strength also...
Reaction Involved: NO3- + 3Fe2+ + 4H+ → NO + 3Fe2 + 2H2O [Fe(H2O) 6]SO4 + NO → [Fe(H2O) 5NO]SO4 (brown coloured complex)
Identification: Halide A - PCl5 (yellowish-white powder) Halide B - PCl3 (colourless oily liquid) Reaction Involved: PCl3 + 3H2O H3PO3 + 3HCl (Hydrolysis of PCl5) PCl5 + H2O POCl3+ 2HCl PCl5 +...
Fluorine is the most potent oxidizing agent and can oxidize sulfur in its high oxidation state (+6) to form SF6. Chlorine is not a good oxidizing agent, it cannot oxidize sulfur in its high...
H2O has a higher bond angle than H2S because as we move from oxygen to sulfur the size of the central atom increases and electronegativity decreases due to which bond moving from the central atom...
Chlorine has some empty area in the d orbital which is why it can show an oxidation state of +3. Fluorine has no vacancy in the d orbital, it cannot show a good oxidation state. Fluorine shows only...
The nitric acid in the form of a gas is present in the form of a monomer. It contains only one unpaired electron and is therefore paramagnetic. In the solid state, it exists as a dimer (N2O2). There...
The size of the axial bond is greater than the size of the equatorial bond to endure repulsion because the three equatorial bonds create more repulsion. The two axial P-Cl bonds are therefore longer...
With water, the PH3 does not form any hydrogen bond. It therefore does not dissolve in water and evaporates as a gas and forms bubbles while the ammonia forms the hydrogen bond and dissolves in water.
Reaction Involved: NH3 + O2 → 4NO + 6H2O The platinum gauze acts as a catalyst to speed up the reaction.
The dissolution of SO3 in water is very exothermic. This leads to the formation of tiny droplets that are corrosive and can even attack the lead pipes used to cover the tower in the communication...
(i) The only type of interactions between particles of noble gases is due to weak dispersion forces. (ii) Ionisation enthalpy of molecular oxygen is very close to that of xenon. (iii) Hydrolysis of...
(i) CaF2+ H2SO4 → CaSO4+ 2HF (ii) 2HI + H2SO4 → I2 + SO2+ 2H2O (iii) Cu + 2H2SO4 → CuSO4 + SO2 + 2H2O (iv) NaCl + H2SO4 → NaHSO4 + HCl Correct Answers: (ii) 2HI + H2SO4 → I2 + SO2+ 2H2O...
(i) S–S bond is present in H2S2O6 (ii) In peroxosulphuric acid (H2SO5) sulphur is in +6 oxidation state. (iii) Iron powder along with Al2O3 and K2O is used as a catalyst in the preparation of NH3 by...
(i) As2O3< SiO2< P2O3< SO2 Acid strength. (ii) AsH3< PH3< NH3 Enthalpy of vaporization. (iii) S < O < Cl < F More negative electron gain enthalpy. (iv) H2O > H2S > H2Se...
(i) All three N—O bond lengths in HNO3 are equal. (ii) All P—Cl bond lengths in PCl5 molecule in the gaseous state are equal. (iii) P4 molecule in white phosphorus have angular strain therefore...
(i) It acts as a bleaching agent in moist conditions. (ii) Its molecule has linear geometry. (iii) It’s dilute solution is used as a disinfectant. (iv) It can be prepared by the reaction of dilute...
(i) Among halogens, radius ratio between iodine and fluorine is maximum. (ii) Leaving F—F bond, all halogens have weaker X—X bond than X—X’ bond in interhalogens. (iii) Among interhalogen compounds,...
(i) It has 6 lone pairs of electrons. (ii) It has six P–P single bonds. (iii) It has three P–P single bonds. (iv) It has four lone pairs of electrons. Correct Answers: (ii) It has six P–P...
(i) F2 > Cl2 > Br2 > I2 - Oxidising power. (ii) MI > MBr > MCl > MF - Ionic character of metal halide. (iii) F2 > Cl2 > Br2 > I2 - Bond dissociation enthalpy. (iv) HI <...
(i) 0 to +5 (ii) 0 to +3 (iii) 0 to –1 (iv) 0 to +1 Correct Answers: (i) 0 to +5 (iii) 0 to –1 Explanation:
(i) 2 (ii) 3 (iii) 4 (iv) 6 Correct Answer: (i) 2 Explanation: In the preparation of HNO3, we get NO gas by catalytic oxidation of ammonia. The moles of NO produced by the oxidation of two...
(i) +3 (ii) +5 (iii) +1 (iv) –3 Correct Answer: (iii) +1 Explanation: NaH2PO2 = 1 + (2x+1) + x + 2(−2) =0 x−1 = 0 x = +1
(i) NH4+ (ii) SiCl4 (iii) SF4 (iv) SO42- Correct Answer: (iii) SF4 Explanation: The shape of SF4 is not tetrahedral.
(i) H2SO5 and H2S2O8 (ii) H2SO5 and H2S2O7 (iii) H2S2O7 and H2S2O8 (iv) H2S2O6 and H2S2O7 Correct Answer: (i) H2SO5 and H2S2O8 Explanation: Peroxides of Sulphur - H2SO5 and...
(i) Cu (ii) S (iii) C (iv) Zn Correct Answer: (iii) C Explanation: When hot conc. H2SO4 acts as a moderately strong oxidising agent, it oxidises both metals and nonmetals. The element Carbon...
(i) –3 to +3 (ii) –3 to 0 (iii) –3 to +5 (iv) 0 to –3 Correct Answer: (i) –3 to +3 Explanation: A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When an...
(i) both O2 and Xe has the same size. (ii) both O2 and Xe has the same electron gain enthalpy. (iii) both O2 and Xe has almost same ionisation enthalpy. (iv) both Xe and O2 are gases Correct...
(i) covalent solid (ii) octahedral structure (iii) ionic solid with [PCl6]+ octahedral and [PCl4]– tetrahedra (iv) ionic solid with [PCl4]+tetrahedral and [PCl6]– octahedral Correct Answer:...
IonReduction potential Eᶱ/V ClO4–Eᶱ = 1.19V IO4–Eᶱ = 1.65V BrO4 –Eᶱ = 1.74V (i) ClO4–> IO4– > BrO4– (ii) IO4– > BrO4– > ClO4– (iii) BrO4– > IO4– > ClO4– (iv) BrO4– > ClO4– >...
(i) ICl2, ClO2 (ii) BrO2-, BrF2+ (iii) ClO2, BrF (iv) CN-, O3 Correct Answer: (ii) BrO2-, BrF2+ Explanation: BrO2- = 35 + 2 * 8 + 1 => 52 BrF2+ = 35 + 2 * 9 - 1 =>...
(i) H2SO4 reduces HI to I2 (ii) HI is of violet colour (iii) HI gets oxidised to I2 (iv) HI changes to HIO3 Correct Answer: (iii) HI gets oxidised to I2 Explanation: Reaction...
(i) a deep blue precipitate of Cu (OH)2 (ii) a deep blue solution of [Cu (NH3)4]2+ (iii) a deep blue solution of Cu(NO3)2 (iv) a deep blue solution of Cu(OH)2.Cu(NO3)2 Correct Answer: (ii) a...
(i) 3 double bonds; 9 single bonds (ii) 6 double bonds; 6 single bonds (iii) 3 double bonds; 12 single bonds (iv) Zero double bonds; 12 single bonds Correct Answer: (ii) 6 double bonds; 6...
(i) Carbon (ii) Nitrogen (iii) Phosphorus (iv) Boron Correct Answer: (iii) Phosphorus Explanation: The element which is involved in the pπ–dπ bonding is Phosphorus.
(i) CO32-, NO3- (ii) ClO3- , CO32- (iii) SO32-, NO3- (iv) ClO3- , SO32– Correct Answer: (i) CO32-, NO3- Explanation: CO32- and NO3- are the pairs of ions that are isoelectronic and...
(i) HF (ii) HCl (iii) HBr (iv) HI Correct Answer: (i) HF Explanation: HF is the halogen acids that must have the highest bond dissociation enthalpy.
Compound∆diss (E—H)/kJ mol–1 NH3389 PH3322 AsH3297 SbH3255 (i) NH3 (ii) PH3 (iii) AsH3 (iv) SbH3 Correct Answer: (iv) SbH3 Explanation: SbH3 is the compound that will act as the strongest...
(i) It is highly poisonous and has smelled like rotten fish. (ii) It’s a solution in water decomposes in the presence of light. (iii) It is more basic than NH3 (iv) It is less basic than NH3 ...
(i) H3PO2 (ii) H3BO3 (iii) H3PO4 (iv) H3PO3 Correct Answer: (iii) H3PO4 Explanation: H3PO4 is the acid that form three series of salts.
(i) The low oxidation state of phosphorus (ii) Presence of two –OH groups and one P–H bond (iii) Presence of one –OH group and two P–H bonds (iv) High electron gain enthalpy of phosphorus ...
(i) N2O, PbO (ii) NO2, PbO (iii) NO, PbO (iv) NO, PbO2 Correct Answer: (ii) NO2, PbO Explanation: Reaction Involved - 2Pb(NO3)2 → 2PbO + 4NO2 + O2
(i) Nitrogen (ii) Bismuth (iii) Antimony (iv) Arsenic Correct Answer: (i) Nitrogen Explanation: The element that do not show allotropy is Nitrogen.
(i) 3 (ii) 5 (iii) 4 (iv) 6 Correct Answer: (iii) 4 Explanation: Maximum covalency of nitrogen is 4.
(i) Single N–N bond is stronger than the single P–P bond. (ii) PH3 can act as a ligand in the formation of a coordination compound with transition elements. (iii) NO2 is paramagnetic. (iv) Covalency...
(i) [Fe(H2O)5 (NO)]2+ (ii) FeSO4.NO2 (iii) [Fe(H2O)4 (NO)]2+ (iv) FeSO4.HNO3 Correct Answer: (i) [Fe(H2O)5 (NO)]2+ Explanation: A brown ring is formed in the ring test for NO3– ion. It is...
(i) Bi2O5 (ii) BiF5 (iii) BiCl5 (iv) Bi2S5 Correct Answer: (ii) BiF5 Explanation: Due to the inert pair effect bismuth only exhibit +3 oxidation state and form trihalides. But due to the size...
(i) N2 in both cases (ii) N2 with ammonium dichromate and NO with barium azide (iii) N2O with ammonium dichromate and N2 with barium azide (iv) N2O with ammonium dichromate and NO2 with barium azide...