Since Volume (V) = ……….(i) ……….(ii) It is given that increase in side = 3% = ……….(iii) Since approximate change in volume V of cube = = = cubic meters Therefore,The correct option is ...
If f(x) = 3x^ 2 + 15x + 5, then the approximate value of f (3.02) is (A) 47.66 (B) 57.66 (C) 67.66 (D) 77.66
Let ……….(i) ……….(ii) Changing to and to in eq. (i), = ……….(iii) Here, and From eq. (iii), Since, and is approximately equal to and respectively. From eq. (i) and (ii), = = ...
If the radius of a sphere is measured as 9 m with an error of 0.03 m, then find the approximate error in calculating its surface area.
Let be the radius of the sphere. Surface area of the sphere (S) = · = square meters
If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.
Let be the radius of the sphere and be the error in measuring the radius. Then, according to the question, = 7 m and = 0.02 m Volume of sphere (V) = Approximate error in calculating the...
Find the approximate change in the surface area of a cube of side x metres caused by decreasing the side by 1%.
Since Surface area (S) = It is given that decrease in side = of Since approximate change in surface area S of cube = = = square meters (decreasing)
Find the approximate change in the volume V of a cube of side x metres caused by increasing the side by 1%.
Since Volume (V) = ……….(i) ……….(ii) It is given that increase in side = 1% = ……….(iii) Since approximate change in volume V of cube = = = cubic...
Find the approximate value of f (5.001), where f(x) = x ^3 – 7x^ 2 + 15.
Let ……….(i) ……….(ii) Changing to and to in eq. (i), = ……….(iii) Here, and From eq. (iii), Since, and is approximately equal to and respectively. From eq. (i) and (ii), = = ...
Find the approximate value of f(2.01), where f (x) = 4x ^2 + 5x + 2.
Let ……….(i) = ……….(ii) Changing to and to in eq. (i), = ……….(iii) Here, and From eq. (iii), Since, and is approximately equal to and respectively. From eq. (i) and (ii), ...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xv) (32.15)^1/5
(xv) Let ……….(i) = ……….(ii) Now, from eq. (i), = = ……….(iii) Here and Then = = Since, and is approximately equal to and respectively. From eq. (ii), = 0.001875 Therefore,...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xiii) (81.5)^1/4 (xiv) (3.968)^3/2
(xii) Let ……….(i) = ……….(ii) Now, from eq. (i), = = ……….(iii) Here and Then = = Since, and is approximately equal to and respectively. From eq. (ii), = 0.00462 Therefore,...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xi) (0.0037)^1/2 (xii) (26.57)^1/3
(xi) Let ……….(i) = ……….(ii) Now, from eq. (i), = Here, and , then = Since, and is approximately equal to and respectively. From eq. (ii), = Therefore, approximately value...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (ix) (82)^1/4 (x) (401)^1/2
(ix) Let ……….(i) = ……….(ii) Now, from eq. (i), = = ……….(iii) Here and Then = = Since, and is approximately equal to and respectively. From eq. (ii), Therefore, approximate...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (vii) (26)^1/3 (viii) (255)^1/4
(vii) Let ……….(i) = ……….(ii) Now, from eq. (i), = Here, and , then = Since, and is approximately equal to and respectively. From eq. (ii), = Therefore, approximately value...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (v) (0.999)^1/10 (vi) (15)^1/4
(v) Let ……….(i) = ……….(ii) Now, from eq. (i), = = ……….(iii) Here and Then = = Since, and is approximately equal to and respectively. From eq. (ii), Therefore, approximate...
Using differentials, find the approximate value of each of the following up to 3 places of decimal.(iii) √0.6 (iv) ∛(0.009)
(iii) Let ……….(i) = ……….(ii) Now, from eq. (i), = Here, and , then = Since, and is approximately equal to and respectively. From eq. (ii), = Therefore, approximately value...
Using differentials, find the approximate value of each of the following up to 3 places of decimal. (i)√ 25.3 (ii) √49.5
Assume ……….(i) = ……….(ii) Now, from eq. (i), = Here, and , then = Since, and is approximately equal to and respectively. From eq. (ii), = 0.03 Therefore, approximately value...