Coordination Compounds

Match the compounds given in Column I with the oxidation state of cobalt present in it (given in Column II) and assign the correct code. with the oxidation state of cobalt present in it (given in Column II) and assign the correct code.

  Solution: \[\left( c \right)\text{ }\left( A\text{ }\to \text{ }5 \right),\text{ }\left( B\text{ }\to \text{ }1 \right),\text{ }\left( C\text{ }\to \text{ }4 \right),\text{ }\left( D\text{...

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Match the coordination compounds given in Column I with the central metal atoms given in Column II and assign the correct code : Code : (i) A (5) B (4) C (1) D (2) (ii) A (3) B (4) C (5) D (1) (iii) A (4) B (3) C (2) D (1) (iv) A (3) B (4) C (1) D (2)

Solution: \[\left( b \right)\text{ }\left( A\text{ }\to 5 \right),\text{ }\left( B\text{ }\to \text{ }4 \right),\text{ }\left( C\text{ }\to \text{ }1 \right),\text{ }\left( D~\to 2 \right)\]  ...

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An aqueous pink solution of cobalt(II) chloride changes to deep blue on the addition of an excess of HCl. This is because____________. (a) [Co(H2O)6]2+ is transformed into [CoCl6]4– (b) [Co(H2O)6]2+ is transformed into [CoCl4]2– (c) tetrahedral complexes have smaller crystal field splitting than octahedral complexes. (d) tetrahedral complexes have larger crystal field splitting than octahedral complex.

Solution: (b, c) Aqueous pink arrangement of cobalt (II) chloride is because of electronic progress of electron from t2g to eg energy level of [Co(H2O)6]2+ complex. At the point when overabundance...

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Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are (a) linkage isomers (b) coordination isomers (c) ionisation isomers (d) geometrical isomers

Solution: (a) The ligands having two distinctive holding locales are known as ambident ligands e.g., NCS, NO2, and so forth Here, NCS has two restricting locales at N and S. Subsequently, NCS...

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When 0.1 mol COCl3(NH3)5 is treated with excess of AgNO3, 0.2 mol of AgCl are obtained. The conductivity of solution will correspond to (a) 1:3 electrolyte (b) 1:2 electrolyte (c) 1:1 electrolyte (d) 3:1 electrolyte

Solution: (b) One mole of AgNO3 accelerates one mole of chloride particle. In the above response, when 0.1 mole COCl3(NH3)5 is treated with abundance of AgNO3, 0.2 mole of AgCl are obtained hence,...

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The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH3)6]3+, [Co(CN)6]3–, [Co(H2O)6]3+ (a) [Co(CN)6]3–> [Co(NH3)6]3+>[Co(H2O)6]3+ (b) [Co(NH3)6]3+> [Co(H2O)6]3+> [Co(CN)6]3– (c) [Co(H2O)6]3+> [Co(NH3)6]3+> [Co(CN)6]3– (d) [Co(CN)6]3–> [Co(NH3)6]3+> [Co(H2O)6]3+

Solution:  

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A coordination compound CrCl3.4H2O hastens silver chloride when treated with silver nitrate. The molar conductance of its answer relates to a sum of two particles. Compose the primary recipe of the compound and name it.

Solution: Assuming it structures silver chloride, there is without one chlorine iota outside the coordination circle. The primary recipe must be [Cr(H2O)4Cl2]Cl. The name of this complex is...

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What will be the correct order for the wavelengths of absorption in the visible region for the following:
 \[{{[\mathbf{Ni}{{(\mathbf{N}{{\mathbf{O}}_{\mathbf{2}}})}_{\mathbf{6}}}]}^{\mathbf{4}}},\text{ }{{[\mathbf{Ni}{{(\mathbf{N}{{\mathbf{H}}_{\mathbf{3}}})}_{\mathbf{6}}}]}^{\mathbf{2}+}},\text{ }{{[\mathbf{Ni}{{({{\mathbf{H}}_{\mathbf{2}}}\mathbf{O})}_{\mathbf{6}}}]}^{\mathbf{2}+}}?\]

Because all of the complexes have the same metal ion, the energy absorption is determined by the ligands' CFSE values. The ligands' CFSE values are in the order of H2O <  NH3 < NO2- according...

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Amongst the following, the most stable complex is \[\left( i \right)\text{ }{{[Fe{{({{H}_{2}}O)}_{6}}]}^{3+}}\left( ii \right)\text{ }{{[Fe{{(N{{H}_{3}})}_{6}}]}^{3+}}~\left( iii \right)\text{ }{{[Fe{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{3}}~~~\left( iv \right)\text{ }{{[FeC{{l}_{6}}]}^{3}}\]

Fe has an oxidation state of +3 in all circumstances. The chelating ligand (C2O4)3 is a bidentate chelating ligand that produces chelating rings. As a result, the most stable complex is ( iii ).

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What is the coordination entity formed when an excess of aqueous KCN is added to an aqueous solution of copper sulfate? Why is it that no precipitate of copper sulphide is obtained when \[{{H}_{2}}S\left( g \right)\] is passed through this solution?

As a result of the foregoing procedure, the coordination entity obtained is K2[Cu(CN)4 ].The above coordination entity does not ionize to produce Cu2+ ions since it is extremely stable. When...

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