Sample space is the set of first 100 natural numbers. n (S) = 100 Let ‘A’ be the event of choosing the number such that it is divisible by 4 n (A) = [100/4] = [25] = 25 {where [.] represents...
Let ‘E’ denotes the event that student passes in English examination. And ‘H’ be the event that student passes in Hindi exam. It is given that, P (E) = 0.75 P (passing both) = P (E ∩ H) = 0.5 P...
A card is drawn from a deck of 52 cards. Let ‘S’ denotes the event of card being a spade and ‘K’ denote the event of card being ace. As we know that a deck of 52 cards contains 4 suits (Heart,...
If a dice is thrown twice, it has a total of 36 possible outcomes. If S represents the sample space then, n (S) = 36 Let ‘A’ represent events the event such that 3 comes in the first throw. A =...
Sample space is the set of first 500 natural numbers. n (S) = 500 Let ‘A’ be the event of choosing the number such that it is divisible by 3 n (A) = [500/3] = [166.67] = 166 {where [.] represents...
In a single throw of 2 die, we have total 36 outcomes possible. Say, n (S) = 36 Where, ‘S’ represents sample space Let ‘A’ denotes the event of getting a double. So, A = {(1,1), (2,2), (3,3), (4,4),...
A card is drawn from a deck of 52 cards is given. Let ‘S’ denotes the event of card being a spade and ‘K’ denote the event of card being King. As we know that a deck of 52 cards contains 4 suits...
Let A and B be two events. As, out of 2 events, only one can happen at a time which means no event have anything common. ∴ We can say that A and B are mutually exclusive events. So, by definition of...
As, out of 3 events, only one can happen at a time which means no event have anything common. So, A, B and C are mutually exclusive events. Now, by definition of mutually exclusive events we know, P...
A and B are two mutually exclusive events is given P (A) = 1/2 and P (B) = 1/3 We need to find P (A ‘or’ B). P (A or B) = P (A ∪ B) So by definition of mutually exclusive events we know, P (A ∪ B) =...
A and B are two events is given P (A′) = 0.5, P (A ∩ B) = 0.3 and P (A ∪ B) = 0.8 Since, P (A′) = 1 – P (A) P (A) = 1 – 0.5 = 0.5 We need to find P (B). By definition of P (A or B) under axiomatic...
A and B are two events is given P (A) = 0.3, P (B) = 0.5 and P (A ∪ B) = 0.5 We need to find P (A ∩ B). By definition of P (A or B) under axiomatic approach we know, P (A ∪ B) = P (A) + P (B) – P (A...
$$ \begin{tabular}{|l|l|l|l|l|} \hline & $\mathrm{P}(\mathrm{A})$ & $\mathrm{P}(\mathrm{B})$ & $\mathrm{P}(\mathrm{A} \cap \mathrm{B})$ & $\mathrm{P}(\mathrm{AUB})$ \\ \hline $\text { (i) }$ &...
A and B are two events is given P (A) = 0.54, P (B) = 0.69 and P (A ∩ B) = 0.35 By definition of P (A or B) under axiomatic approach we can write, P (A ∪ B) = P (A) + P (B) – P (A ∩ B) (i) P (A ∩...
A and B are two events is given P (A) = 0.54, P (B) = 0.69 and P (A ∩ B) = 0.35 By definition of P (A or B) under axiomatic approach we can write, P (A ∪ B) = P (A) + P (B) – P (A ∩ B) (i) P (A ∪ B)...
A and B are two mutually exclusive events is given to us. P (A) = 0.4 and P (B) = 0.5 By definition of mutually exclusive events we can write, P (A ∪ B) = P (A) + P (B) (i) P (A′ ∩ B) P (only B) = P...
A and B are two mutually exclusive events is given to us. P (A) = 0.4 and P (B) = 0.5 By definition of mutually exclusive events we can write, P (A ∪ B) = P (A) + P (B) (i) P (A ∪ B) = P (A) + P (B)...