We realize that upsides of tan x repeat after a time frame of \[\pi \text{ }or\text{ }180{}^\circ \] So we get By additional computation
Find the values of the trigonometric functions in
We realize that upsides of transgression x repeat after a time frame of \[2\pi \text{ }or\text{ }360{}^\circ \] So we get By additional estimation
Find the values of the trigonometric functions in
We realize that upsides of tan x repeat after a timespan of \[\pi \text{ }or\text{ }180{}^\circ \] So we get By additional estimation We get \[=\text{ }tan\text{ }60o\] \[=\text{ }\surd...
Find the values of the trigonometric functions in cosec (–1410°)
We realize that upsides of cosec x repeat after a time frame of \[2\pi \text{ }or\text{ }360{}^\circ \] So we get By additional computation \[=\text{ }cosec\text{ }30o\text{ }=\text{ }2\]...
Find the values of the trigonometric functions sin 765°
We realize that upsides of sin x repeat after a time frame of $$ \[2\pi \text{ }or\text{ }360{}^\circ \] So we get By additional computation \[=\text{ }sin\text{ }45o\] \[=\text{ }1/\surd...
Find the values of other five trigonometric functions tan x = -5/12, x lies in second quadrant
It is given that \[tan\text{ }x\text{ }=\text{ }\text{ }5/12\] We can compose it as We realize that \[1\text{ }+\text{ }tan2\text{ }x\text{ }=\text{ }sec2\text{ }x\] We can compose it as...
Find the values of other five trigonometric functions sec x = 13/5, x lies in fourth quadrant
It is given that sec x = 13/5 We can write it as We know that sin2 x + cos2 x = 1 We can write it as sin2 x = 1 – cos2 x Substituting the values sin2 x = 1 – (5/13)2 sin2 x = 1 – 25/169 = 144/169...
cot x = 3/4, x lies in third quadrant
It is given that We can compose it as We realize that We can compose it as Subbing the qualities Here x lies in the third quadrant so the worth of sec x will be negative We can compose it...
Find the values of other five trigonometric functions sin x = 3/5, x lies in second quadrant
It is given that sin x = 3/5 We can write it as We know that sin2 x + cos2 x = 1 We can write it as cos2 x = 1 – sin2 x
Find the values of other five trigonometric functions cos x = -1/2, x lies in third quadrant.
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