Solution:- Let us consider the assumed mean A = \[64\]. Here h = \[1\] Mean, \[\bar{X}=A+\frac{\sum\limits_{i=1}^{a}{{{f}_{i}}{{y}_{i}}}}{N}\times h\] Where A = \[64\], h = \[1\]...

Solution:- The given data is converted into continuous frequency distribution by subtracting \[0.5\] from the lower limit and adding the \[0.5\] to the upper limit of each class intervals and append...

Solution:- Draw  the table of the given data and append other columns after calculations. The class interval containing \[{{N}^{th}}/2\]or \[25\] item is \[20-30\] So, \[20-30\]is the median class....

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N= \[\sum\limits_{i=1}^{6}{{{f}_{i}}=100}\],...

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N= \[\sum\limits_{i=1}^{8}{{{f}_{i}}=50}\],...

Solution:- Draw a table of the given data and append other columns after calculations. Now, N = 29, which is odd. The cumulative frequency greater than \[14.5\] is \[21\], for which the...

Solution:- Draw a table of the given data and append other columns after calculations. We know that, N = \[26\], which is even. So, median is the mean of the \[13\]and \[14\] observations. Both of...

Solution:- Draw a table of the given data and append other columns after calculations. The sum of calculated data, N = \[\sum\limits_{i=1}^{5}{{{f}_{i}}}=80\],...

  \[{{x}_{i}}\] \[5\] \[10\] \[15\] \[20\] \[25\] \[{{f}_{i}}\] \[7\] \[4\] \[6\] \[3\] \[5\] Solution:- We have to make the table of the given data and append other columns after calculations....

Solution:- To find the median arrange the given observations in ascending order, \[36,42,45,46,46,49,51,53,60,72\] Total number of observations = \[10\] Then, Median = (\[{{(10/2)}^{th}}\]...

Solution:- To find the median arrange the given observations in ascending order, \[10,11,11,12,13,13,14,16,16,17,17,18\] Total number of observations = \[12\] Then, Median = (\[{{(12/2)}^{th}}\]...

Solution:- To find mean deviation, first we have to find mean\[(\overline{x})\] \[\overline{x}=\frac{1}{10}\sum\limits_{i=1}^{10}{{{x}_{i}}}=\frac{500}{10}=50\] Determine the respective values of...

Solution:- Given data \[4\], \[7\], \[8\], \[9\], \[10\], \[12\], \[13\], \[17\] To find mean deviation,  first we have to find mean\[(\overline{x})\]...