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CBSE Class 11 Lakhmir Singh Chemistry
Chemistry

Consider the isoelectronic species, Na+, Mg2+, F–and O2–. The correct order of increasing length of their radii is _________.
\[\left( \mathbf{i} \right)\text{ }{{\mathbf{F}}^{}}~<\text{ }{{\mathbf{O}}^{\mathbf{2}-}}~<\text{ }\mathbf{M}{{\mathbf{g}}^{\mathbf{2}+}}~<\text{ }\mathbf{N}{{\mathbf{a}}^{+}}\]
\[\left( \mathbf{ii} \right)\text{ }\mathbf{M}{{\mathbf{g}}^{\mathbf{2}+}}~<\text{ }\mathbf{N}{{\mathbf{a}}^{+}}<\text{ }{{\mathbf{F}}^{}}<\text{ }{{\mathbf{O}}^{\mathbf{2}-}}\]
\[\left( \mathbf{iii} \right)\text{ }{{\mathbf{O}}^{\mathbf{2}-}}<\text{ }{{\mathbf{F}}^{}}~<\text{ }\mathbf{N}{{\mathbf{a}}^{+}}<\text{ }\mathbf{M}{{\mathbf{g}}^{\mathbf{2}+}}\]
\[\left( \mathbf{iv} \right)\text{ }{{\mathbf{O}}^{\mathbf{2}-}}~<\text{ }{{\mathbf{F}}^{}}~<\text{ }\mathbf{M}{{\mathbf{g}}^{\mathbf{2}+}}~<\text{ }\mathbf{N}{{\mathbf{a}}^{+}}\]

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Option (ii) is the answer. Radius of elements increase as we move from left to right in a period. These are isoelectronic species having same number of electrons. As we move from left to right, from...

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