Let us assume R and r be the radii of the top and base of the bucket respectively, Let us assume h be its height of the bucket. Then, according to the question we have $R=20cm$, $r=10cm$, $h=30cm$...
As per the given information, A milk container in a form of frustum of a cone with, Radius of the lower end $\left( {{r}_{1}} \right)=8cm$ And radius of the upper end $\left( {{r}_{2}} \right)=20cm$...
According to the given data in the question, Height of frustum (h) $=8m$ (given) Bigger and smaller radii of the frustum cone are $13cm$ and $7cm$. Therefore, ${{r}_{1}}=13cm$ and ${{r}_{2}}=7cm$...
The height of frustum cone $=12cm$ (given) Bigger and smaller radii of a frustum cone are $12cm$ and $3cm$ respectively. (given) Therefore , ${{r}_{1}}=12cm;{{r}_{2}}=3cm$ Let us assume that the...
As per the given data in question, Height of the bucket (h) $=24cm$ Radius of the small and big circular ends of the bucket $5cm$ and $15cm$ respectively. So, ${{r}_{1}}=5cm,{{r}_{2}}=15cm$ Let us...
According to the given information, Let us asssume the radius of the small cone be r cm And, the radius of the big cone be R cm It is given, height of the big cone is $20cm$ Let us also assume the...
According to the given information, Let us asssume the radius of the small cone be r cm And, the radius of the big cone be R cm It is given, height of the big cone is $20cm$ Let us also assume the...
Given data as per the question, Height of the conical bucket asgiven in the question $=45cm$ Radii of the bigger and smaller circular ends of the conical bucket are $28cm$ and $7cm$ respectively....
As per the given data, Perimeter of the upper end of a frustum of a right circular cone $=44cm$ So, $2\pi {{r}_{1}}=44$ $2\left( 22/7 \right){{r}_{1}}=44$ (radius of upper end of a frustum of a...
As per the given data, The base diameter of cone $\left( {{d}_{1}} \right)$ $=20cm$ So, the radius of the base of the cone $\left( r_{1}^{{}} \right)$ $=20/2cm=10cm$ The top diameter of...
As per the given information, Diameter of the top of the bucket $=40cm$ So, the radius of the top of the bucket $\left( {{r}_{1}} \right)$ $=40/2=20cm$ Diameter of the bottom part of the bucket...