As per the inquiry, In a right point ΔABC is which ∠B = 90°, a circle is drawn with AB as distance across meeting the hypotenuse AC at P. Likewise PQ is a digression at P To Prove: PQ separates BC...

As per the inquiry, Two circles with focuses O and O' of radii 3 cm and 4 cm, individually meet at two focuses P and Q, to such an extent that OP and O'P are digressions to the two circles and PQ is...

As per the inquiry, A circle with focus O and AC as a measurement and AB and BC as two harmonies additionally AT is a digression at point A To Prove : ∠BAT = ∠ACB Verification : ∠ABC = 90° [Angle in...

As per the inquiry, From an outside point P, two digressions, PA and PB are attracted to a circle with focus O. At a point E on the circle digression is drawn which crosses PA and PB at C and D,...

As indicated by the inquiry, A triangle ABC with BC = a , CA = b and AB = c . Likewise, a circle is engraved which contacts the sides BC, CA and AB at D, E and F individually and s is semi-border of...

As per the inquiry, A Hexagon ABCDEF encompass a circle. To demonstrate: Stomach muscle + CD + EF = BC + DE + FA Verification: Digressions drawn from an outside highlight a circle are equivalent....

As indicated by the inquiry, Abdominal muscle = CD Development: Produce AB and CD, to converge at P. Confirmation: Think about the circle with more noteworthy span. Digressions drawn from an outside...

Leave the lines alone l1 and l2. Expect that O contacts l₁ and l₂ at M and N, We get, OM = ON (Radius of the circle) In this way, From the middle "O" of the circle, it has equivalent separation from...

As per the inquiry, By RHS rule, ΔOBC and ΔOBD are harmonious By CPCT ∠OBC and ∠ OBD are equivalent In this way, \[\angle OBC\text{ }=\angle OBD\text{ }=60{}^\circ \] In triangle OBC, \[cos\text{...

We realize that, Sweep ⊥ Tangent = OR ⊥ PR i.e., ∠ORP = 90° Similarly, Sweep ⊥ Tangent = OQ ⊥PQ ∠OQP = 90° In quadrilateral ORPQ, Amount of every single inside point = 360º \[\angle ORP\text{...

From the figure, Harmony AB = 8 cm OC is opposite to the harmony AB AC = CB = 4 cm In right triangle OCA \[OC2\text{ }+\text{ }CA2\text{ }=\text{ }OA2\] \[OC2\text{ }=\text{ }52\text{ }\text{...

True, Digression is consistently opposite to the span at the resource. Subsequently, ∠RPT = 90 Assuming 2 digressions are drawn from an outer point, they are similarly disposed to the line fragment...

True, Defense: The point between two digressions to a circle might be 0°only when both digression lines concur or are corresponding to one another.

True, Defense: Think about the figure of a circle with focus O. Leave PT alone a digression drawn from outer point P. Presently, Joint OT. OT ⏊ PT We realize that, Digression anytime on the circle...

False, Support: Length of digression from an outside point P on a circle might possibly be more prominent than the sweep of the circle.

False, Support: For instance, Think about the given figure. In which we have a circle with focus O and AB a harmony with ∠AOB = 60° Since, digression to any point on the circle is opposite to the...