Exercise 11.1

If the circumference of a circle and the perimeter of a square are equal, then (A) Area of the circle = Area of the square (B) Area of the circle > Area of the square (C) Area of the circle < Area of the square (D) Nothing definite can be said about the relation between the areas of the circle & square.

The correction option is (B) Area of the circle > Area of the square Explanation: From  the given question, Circumference of a circle of radius r  = Perimeter of a square of side a Let us take  r...

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If the sum of the circumferences of two circles with radii \[R1\] and \[R2\] is equal to the circumference of a circle of radius \[R\], then (A) \[{{R}_{1}}+{{R}_{2}}=R\] (B) \[{{R}_{1}}+{{R}_{2}}>R\] (C) \[{{R}_{1}}+{{R}_{2}}<R\] (D) Nothing definite can be said about the relation among \[{{R}_{1}}\], \[{{R}_{2}}\] & \[R\].

The Correct option(A) \[{{R}_{1}}+{{R}_{2}}=R\] Explanation: From the given question, We got sum of the circumferences of two circles with radii \[R1\] and \[R2\] is equal to the circumference of a...

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If the sum of the areas of two circles with radii \[R1\] and \[R2\] is equal to the area of a circle of radius \[R\], then (A) \[{{R}_{1}}+{{R}_{2}}=R\] (B) \[R_{1}^{2}+R_{2}^{2}={{R}^{2}}\] (C) \[{{R}_{1}}+{{R}_{2}}<R\] (D) \[R_{1}^{2}+R_{2}^{2}<{{R}^{2}}\]

The Correct option is (B) \[R_{1}^{2}+R_{2}^{2}={{R}^{2}}\] Explanation: From the given question, We got sum of the areas of two circles with radii \[R1\] and \[R2\] is equal to the area of a circle...

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