Solution:
On dividing \[380\]by \[16\]we get,\[23\]as the quotient and\[12\]as the remainder.
Now,
since the LCM is not exactly divisible by the HCF its can be said that two numbers cannot have \[16\] as their HCF and\[380\]as their LCM.
Solution:
On dividing \[380\]by \[16\]we get,\[23\]as the quotient and\[12\]as the remainder.
Now,
since the LCM is not exactly divisible by the HCF its can be said that two numbers cannot have \[16\] as their HCF and\[380\]as their LCM.