Solution:

Here, we have \[N\text{ }=\text{ }250,\]

So, \[N/2\text{ }=\text{ }250/\text{ }2\text{ }=\text{ }125\]

The cumulative frequency just greater than \[N/\text{ }2\text{ }is\text{ }127\]then median class is \[50\text{ }\text{ }60\]such that \[L\text{ }=\text{ }50,\text{ }f\text{ }=\text{ }31,\text{ }F\text{ }=\text{ }96,\text{ }h\text{ }=\text{ }60\text{ }-50\text{ }=\text{ }10\]

\[=\text{ }50\text{ }+\text{ }9.35\]                         \[\]

\[=\text{ }59.35\]