(i) Cl–(aq.) →1/2Cl2 (g) + e– ; E°cell = 1.36V
(ii) 2H2O(l) → O2(g0 + 4H+ + 4e- ; E°cell = 1.23V
(iii) Na+(aq) + e- → Na(s) ; E°cell = 2.71V
(iv) H+(aq) + e- → 1/2H2(g) ; E°cell = 0.00V
Correct Answer: (i) Cl–(aq.) →1/2Cl2 (g) + e– ; E°cell = 1.36V
Explanation:
Reaction Involved – Cl– (aq.) →1/2Cl2 (g) + e–
E°cell = 1.36V