Answer is (3)
$BF_3$
Number of electrons around boron atom is 6 .
Hybridization of $B$ is sp².
Shape is trigonal planar.
$\mathrm{BF}_{3}$ is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are:
(1) $\mathrm{sp}^{3}$ and 4
(2) $\mathrm{sp}^{3}$ and 6
(3) $\mathrm{sp}^{2}$ and 6
(4) $\mathrm{sp}^{2}$ and 8
(1) $\mathrm{sp}^{3}$ and 4
(2) $\mathrm{sp}^{3}$ and 6
(3) $\mathrm{sp}^{2}$ and 6
(4) $\mathrm{sp}^{2}$ and 8
$\mathrm{BF}_{3}$ is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are:
(1) $\mathrm{sp}^{3}$ and 4
(2) $\mathrm{sp}^{3}$ and 6
(3) $\mathrm{sp}^{2}$ and 6
(4) $\mathrm{sp}^{2}$ and 8
(1) $\mathrm{sp}^{3}$ and 4
(2) $\mathrm{sp}^{3}$ and 6
(3) $\mathrm{sp}^{2}$ and 6
(4) $\mathrm{sp}^{2}$ and 8