Answer –
We are given the angle of declination, θ = 12°
Angle of dip, given by δ = 60°
Horizontal component of earth’s magnetic field is given by BH = 0.16 G
Earth’s magnetic field at the given location is = B
We can relate B and BH in following manner –
${{B}_{H}}=B\cos \delta $
Rearranging the above relation, we get –
$B=\frac{{{B}_{H}}}{\cos \delta }=\frac{0.16}{\cos {{60}^{\circ }}}$$$
$B=0.32G$
The magnetic field of the Earth is located in the vertical plane, 12 degrees west of the geographic meridian, and forms a 60-degree (upward) angle with the horizontal direction. It is 0.32 G in magnitude.