An ideal transformer converts 220Va.c. to 3.3 k.V a.c to transmit a power of 4.4 kW. If primary coil has 600 turns, then alternating current in secondary coil is
An ideal transformer converts 220Va.c. to 3.3 k.V a.c to transmit a power of 4.4 kW. If primary coil has 600 turns, then alternating current in secondary coil is
  1. 1/3A
  2. 4/3A
  3. 5/3A
  4. 7/3A

Solution; The correct answer is B. 4/3 A

Suppose that there is no loss in power transmission:

$ {{E}_{1}}{{I}_{1}}={{E}_{2}}{{I}_{2}} $

$ {{I}_{2}}=\frac{{{E}_{1}}}{{{E}_{2}}}{{I}_{1}} $

$ {{E}_{1}}=220V~and,\,\,{{E}_{2}}=3.3kV=3300V $

$ P={{E}_{1}}{{I}_{1}} $

$ {{I}_{1}}=\frac{P}{{{E}_{1}}}=\frac{4.4\times {{10}^{3}}}{220}=20A $

$ {{I}_{2}}=\frac{220}{3300}\times 20 $

$ {{I}_{2}}=1.3A $