solution;
Given height of the tent above the ground = 85 m
Height of the cylindrical part, H = 50 m
height of the cone, h = 85-50
h = 35 m
Diameter of the base, d = 168 m
Radius of the base of cylindrical part, r = d/2 = 168/2 = 84 m
Radius of cone, r = 84 m
Slant height of the cone, l = √(h2+r2)
l = √(352+842)
l = √(1225+7056)
l = √(8281)
l = 91 m
Surface area of tent = curved surface area of cylinder + curved surface area of cone
= 2rH+rl
= r(2H+l)
= (22/7)×84×(2×50+91)
= (22/7)×84×(100+91)
= ((22×84)/7)×191
= (1848/7)×191
= 264×191
= 50424 m2
Adding 20% extra for folds and stitches,
Area of canvas = 50424+ 20% of 50424
= 50424+ (20/100) ×50424
= 50424+ 0.2×50424
= 50424+ 10084.8
= 60508.8 m2
= 60509 m2
Hence the the quantity of canvas required to make the tent is 60509 m2.