Electrons are accelerated by a voltage of $50 \mathrm{kV}$
Charge on an electron, $e=1.6 \times 10^{-19} \mathrm{C}$
Mass of the electron, $m_{e}=9.11 \times 10^{-31} \mathrm{~kg}$
Wavelength of the yellow light is given as $5.9 \times 10^{-7} \mathrm{~m}$
The kinetic energy of the electron, $E=e V$
$=\left(1.6 \times 10^{-19}\right) \times\left(50 \times 10^{3}\right)$
$=8 \times 10^{-15} \mathrm{~J}$
De Broglie wavelength of electron is given as
$\lambda=\frac{h}{\sqrt{2 m_{c} E}}$
$\lambda=\frac{6.6 \times 10^{-34}}{\sqrt{2 \times 9.11 \times 10^{-31} \times 8 \times 10^{-15}}}$
$=5.467 \times 10^{-12} \mathrm{~m}$
The wavelength of the blue light is $10^{5}$ times shorter than that of the yellow light. The wavelength of the light used and the resolving power of the microscope are inversely related. As a result, the electron microscope’s resolving power is $10^{5}$ times larger than that of an optical microscope.