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According to Arrhenius equation rate constant k is equal to A e–E /RT a. Which of the following options represents the graph of ln k vs 1/T
According to Arrhenius equation rate constant k is equal to A e–E /RT a. Which of the following options represents the graph of ln k vs 1/T
CBSE | Chemical Kinetics | Chemistry | Class 12 | Exercise 1 | NCERT Exemplar
According to Arrhenius equation rate constant k is equal to A e–E /RT a. Which of the following options represents the graph of ln k vs 1/T

NCERT Exemplar Solutions of Class 12 Chemistry Chapter 4 Chemical Kinetics-2

 

Correct Answer: Option (i)

Explanation: According to Arrhenius equation, the graph represented in the first option is a straight line with negative slope.

i

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