A uniform magnetic field of $1.5 \mathrm{~T}$ exists in a cylindrical region of a radius of $10.0 \mathrm{~cm}$, its direction parallel to the axis along east to west. A wire carrying a current of $7.0$ A in the north to south direction passes through this region. What is the magnitude and direction of the force on the wire if, the wire in the N-S direction is lowered from the axis by a distance of $6.0 \mathrm{~cm} ?$

3 years ago

When the wire is lowered by $6 \mathrm{~cm}$, then

Then, $x=\sqrt{(10)^{2}-\left(6^{2}\right)}=\sqrt{64}=8 \mathrm{~cm}$

$2 \mathrm{x}=\mathrm{I}_{2}=16 \mathrm{~cm}$

$F_{2}=BII_{2}$=$1.5 \times 7 \times 0.16=1.68 \mathrm{~N}$

Therefore, the force is directed vertically downwards.