A triangle ABC lies in the co-ordinate plane. The co-ordinates of its vertices are A $\left( 2,3 \right)$, B $\left( 4,-4 \right)$and C $$$\left( 6,-7 \right)$. This triangle is reflected in the line y $=0$on to ΔA’B’C’. ΔA’B’C’ in then reflected in the origin onto ΔA”B”C”. Mention down the co-ordinates of ΔA’B’C’ and ΔA”B”C”.

In the question it is mentioned that,

The co–ordinates of its vertices are A $\left( 2,3 \right)$, B $\left( 4,-4 \right)$ and C $\left( 6,-7 \right)$

Then, co-ordinates of ΔA’B’C’ under reflection  within the line y $=0.$

So, A’ = $\left( 2,-3 \right)$

B’ = $\left( 4,4 \right)$

C’ = $\left( 6,7 \right)$

Now, co-ordinates of ΔA”B”C” under reflection in the origin,

A” $=\left( -2,3 \right)$

B” $=\left( -4,-4 \right)$

C” $=\left( -6,-7 \right)$