Answer:
It is given that v0 = 400 Hz and vz = 10 m/s
We know that the velocity of sound in air is
va = 330 m/s
The frequency heard by the observer on the platform is v’.
Therefore, we can write:
v’ = (330)(400)/320
v’ = 412.5 Hz
A train standing at the outer signal of a railway station blows a whistle of frequency 400 Hz still air. The train beings to move with a speed of 10 m/s towards the platform. What is the frequency of the sound for an observer standing on the platform?
A train standing at the outer signal of a railway station blows a whistle of frequency 400 Hz still air. The train beings to move with a speed of 10 m/s towards the platform. What is the frequency of the sound for an observer standing on the platform?