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A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is:
A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is:
Physics
A thermodynamic system undergoes cyclic process ABCDA as shown in fig. The work done by the system in the cycle is:

Option A $\quad \mathrm{P}_{0} \mathrm{~V}_{0}$

Option B $\quad 2 \mathrm{P}_{0} \mathrm{~V}_{0}$

Option C $\frac{\mathrm{P}_{0} \mathrm{~V}_{0}}{2}$

Option D zero

Correct Option is D

Solution:

Work done by the system in the cycle can be given as,

Area under $P-V$ curve & $V$ – axis

For clockwise work, done is positive

For anticlockwise work, done is negative

$\mathrm{W}_{\mathrm{ADEA}}=+\frac{1}{2}\left(2 \mathrm{P}_{0}-\mathrm{P}_{0}\right)\left(2 \mathrm{~V}_{0}-\mathrm{V}_{0}\right)$

$\mathrm{W}_{\mathrm{EBCE}}=-\left(\frac{1}{2}\right)\left(3 \mathrm{P}_{0}-2 \mathrm{P}_{0}\right)\left(2 \mathrm{~V}_{0}-\mathrm{V}_{0}\right)$

$=\frac{\mathrm{P}_{0} \mathrm{~V}_{0}}{2}-\frac{\mathrm{P}_{0} \mathrm{~V}_{0}}{2}=0$

i

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