False,

Clarification:

Let the sweep of circle = r

At the point when a strong ball is by and large fitted inside the cubical box of side a,

We get,

Width of ball = Edge length of 3D shape

\[2r\text{ }=\text{ }a\]

Range, r = a/2

We likewise realize that,

\[Volume\text{ }of\text{ }circle\text{ }=\text{ }4/3\pi r3\]

Volume of ball \[=\text{ }4/3\pi \left( a/2 \right)3\text{ }=\text{ }4/3\pi \left( a3/8 \right)\text{ }=\text{ }1/6\pi a3\]