Given that: \[{{A}_{1}}:\text{ }{{A}_{2}}:\text{ }{{A}_{3}}~=\text{ }4:\text{ }4:\text{ }2\]
So, the probabilities will be
\[P({{A}_{1}})\text{ }=\text{ }4/10,\text{ }P({{A}_{2}})\text{ }=\text{ }4/10\]and \[P({{A}_{3}})\text{ }=\text{ }2/10\],
Where \[{{A}_{1}}\], \[{{A}_{2}}\] and \[{{A}_{3}}\].are the three types of seeds.
Therefore, the required probability is \[16/51\] or \[0.314\].