Volume of water in tank = volume of cuboidal tank up to a stature of 5 m

As per the inquiry,

For cuboidal tank

Length, l = 11 m

Broadness, b = 6 m

Tallness, h = 5m

We realize that the condition to discover the volume of the tank, Volume of tank = lbh, where, l, b and h are the length, expansiveness and tallness of tank separately

Volume of water \[=\text{ }11\left( 6 \right)\left( 5 \right)\text{ }=\text{ }330\text{ }m3\]

We likewise realize that,

Base span of tube shaped tank, r = 3.5 m

Let the stature till which the tube shaped tank is filled = h m

Thus, utilizing the equation,

Volume of a chamber = πr2h, where r is base range and h is the tallness of chamber

Volume of water in barrel shaped tank = π(3.5)2h

\[330\text{ }m\text{ }3\text{ }=\text{ }22/7\text{ }\times \text{ }3.5\text{ }\times 3.5\text{ }\times \text{ }h\]

\[330\text{ }m\text{ }3\text{ }=\text{ }h\text{ }\times \text{ }38.5\]

h = 8.57 m

Consequently, the tallness till which the barrel shaped tank is filled = 8.57 m