If the instantaneous current is t, then
I(t) = 1/R d/dt I(t)
If q is the charge that passes during time t,
dQ/dt = I(t)
1/R d/dt = dQ/dt
When we integrate the equation, we obtain
Q = 0L1L2/2R log (L2 + x/x)
If the instantaneous current is t, then
I(t) = 1/R d/dt I(t)
If q is the charge that passes during time t,
dQ/dt = I(t)
1/R d/dt = dQ/dt
When we integrate the equation, we obtain
Q = 0L1L2/2R log (L2 + x/x)