Answer:
According to the question, the length is:
l = 20 cm =0.2 m
and the frequency is, v = 1237.5 Hz
We know that the velocity of sound in air = 330 m/s
The following expression is:
l = λ/4
λ = 4l
We know that,
v1= v/ λ
v1 = v/4l
v1 = 412.5 Hz
v/v1 = 1237.5/412.5
v/v1 = 3/1
Therefore, the third harmonic will be the one having 1237.5 Hz frequency.