- 0
- 4
- 5
- 6
Solution: The correct answer is A. 0
The frequency for a pipe closed at one end is given by:
f = (n×v )/4L
v = speed of sound = 332m/s
L = length of pipe = 83cm = 0.83m
n = 0,1,2…
f = (1×332)/(4×0.83)
⟹f = 100Hz
Hence, no natural oscillation of frequency less than 100Hz.