A particle performs S.H.M. with amplitude 25 cm and period 3 s. The minimum time required for it to move between two points 12.5 cm on either side of the mean position is

Physics | Physics

A) 0.6 s B) 0.5 s C) 0.4 s D) 0.2 s

Solution: The correct option is B) 0.5 s

$s i n θ = 12.5/25$

$θ = 6 π$

So, the total angle to move is

2 π/6 = π/3

It takes

3 seconds

to rotate by

360 degress

. So, to rotate

60 degress, we will have:

$t = 3/ 360 \times 60$

$t = 0.5 s$

i

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