iG(G+R1) = 2 for 2V range
iG(G+R1+R2) = 20 for 20V range
iG(G+R1+R2+R3) = 200 for 200V range
Solving the above, we get
R1 = 1990 Ω
R2 = 18kΩ
R3 = 180 kΩ
iG(G+R1) = 2 for 2V range
iG(G+R1+R2) = 20 for 20V range
iG(G+R1+R2+R3) = 200 for 200V range
Solving the above, we get
R1 = 1990 Ω
R2 = 18kΩ
R3 = 180 kΩ