The current flowing through the wire (I) has a magnitude of 35 A.

The point’s distance from the wire (r) is 20 cm (0.2 m).

The magnitude of the magnetic field is given at this position by the relation:

$|\overline B | = \frac{{{\mu _0}2I}}{{4\pi r}}$

where,

${\mu _0} = $Permeability of free space

Substituting the values in the equation, we get

$|\overline B | = \frac{{4\pi  \times {{10}^{ – 7}}}}{{4\pi }} \times \frac{{2 \times 35}}{{0.2}}$

As a result, the magnitude of the magnetic field at a distance of 20 cm from the wire is $3.5 \times {10^{ – 5}}T$