(I) = 90 A is the magnitude of the current in the power line.
The point is placed at (r) = 1.5 m below the electrical cable.
As a result, the magnetic field at that location may be computed as follows:
$|\overline B | = \frac{{{\mu _0}2I}}{{4\pi r}}$
where,
${\mu _0} = $Permeability of free space
$ = 4\pi \times {10^{ – 7}}Tm{A^{ – 1}}$
Substituting values in the above equation, we get
$|\overline B | = \frac{{4\pi \times {{10}^{ – 7}}}}{{4\pi }} \times \frac{{2 \times 90}}{{1.5}}$
$ = 1.2 \times {10^{ – 5}}T$
The movement of the current is from east to west. The point is located beneath the electrical cord.
As a result, the magnetic field is oriented southward according to Maxwell’s right-hand thumb rule.