Solution:
Given radius of the hemispherical bowl, r = 3.5 cm = 7/2 cm
Volume of the hemisphere = (2/3)r3
= (2/3)×(22/7)×(7/2)3
= 11×49/6
= 539/6
Hence the volume of the hemispherical bowl is
.
A hemispherical bowl has a radius of 3.5 cm. What would be the volume of water it would contain?
A hemispherical bowl has a radius of 3.5 cm. What would be the volume of water it would contain?