As indicated by the inquiry,

Think about tapered load,

Base Diameter = 9 cm

Thus, base range, r = 4.5 cm

Tallness, h = 3.5 cm

We realize that,

Inclination tallness,

The condition of volume of cone = 1/3πr2h

We realize that,

Volume of rice = Volume of tapered store

\[Volume\text{ }of\text{ }rice\text{ }=\text{ }1/3\pi \left( 4.5 \right)2\left( 3.5 \right)\]

We likewise realize that,

Material needs to simply cover store = Curved surface space of tapered load

What’s more, bended surface space of a cone = πrl

Accordingly, the material required \[=\text{ }\pi \left( 4.5 \right)\left( 5.7 \right)\text{ }=\text{ }80.61\text{ }cm2\text{ }\left[ appx \right]\]