Answers:
(i)
Domain of f = R (set of real numbers)
Square of a real number is always positive or zero.
∴ range of f = R+∪ {0}
(ii)
f(x) = 4
x2 = 4
x2 – 4 = 0
(x – 2)(x + 2) = 0
∴ x = ± 2
∴ {x: f(x) = 4} = {–2, 2}
Answers:
(i)
Domain of f = R (set of real numbers)
Square of a real number is always positive or zero.
∴ range of f = R+∪ {0}
(ii)
f(x) = 4
x2 = 4
x2 – 4 = 0
(x – 2)(x + 2) = 0
∴ x = ± 2
∴ {x: f(x) = 4} = {–2, 2}