We have to give that A dice is thrown once

To find:

(i) The Probability of getting a prime number

(ii) The Probability of getting $2$ or $4$

(iii)The Probability of getting a multiple of $2$ or $3$.

(iv) The Probability of getting an even number

(v)The Probability of getting a number greater than five.

(vi) The Probability of lying between $2$ and $6$

Then Total number on a dice is 6 i.e., $1,2,3,4,5$ and $6$.

(i) Prime numbers on a dice are $2,3$, and $5$. So, the total number of prime numbers is $3$.

As We know that, Probability = Number of favorable outcomes/ Total number of outcomes

Therefore, probability of getting a prime number $=3/5=1/2$

(ii) For getting 2 and 4, clearly the number of favorable outcomes is $2$.

As We know the Probability = Number of favorable outcomes/ Total number of outcomes

So, the probability of getting $2$ or $4=2/6=1/3$