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A closely wound solenoid of 800 turns and area of cross-section 2.5 × 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?
A closely wound solenoid of 800 turns and area of cross-section 2.5 × 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?
Magnetism and Matter | NCERT | Physics
A closely wound solenoid of 800 turns and area of cross-section 2.5 × 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Answer –

It is given that the number of turns in the solenoid, n = 800

Area of cross section is given by, A = 2.5×10-4 m2

And the current in the solenoid, I = 3.0 A

Because a magnetic field develops along its axis, or length, a current-carrying solenoid functions like a bar magnet. The magnetic moment of a current-carrying solenoid is computed as follows:

M = n I A

\[M=800\times 3\times 2.5\times {{10}^{-4}}\]

\[M=0.6J{{T}^{-1}}\]

i

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