Correct Option D
Solution:
Given,
$\mathrm{F}=2 \mathrm{ti}+3 \mathrm{t}^{2}$
As we know,
$F=m a$
which can be represented as,
$F=m \frac{d v}{d t}$
Thus equating with given term and integrating,
$m \frac{d v}{d t}=2 t i+3 t^{2} j$
$\frac{d v}{d t}=\frac{2 t i+3 t^{2} j}{1}$
$\mathrm{v}=\frac{2 \mathrm{t}^{2}}{2} \mathrm{i}+\frac{3 \mathrm{t}^{3}}{3} \mathrm{j}$
According to formula,
$P=\vec{F} \cdot \vec{V}$
So,
$P=\left(2 t i+3 t^{2} j\right) \cdot\left(t^{2} i+t^{3} j\right)$
$P=\left(2 t^{3}+3 t^{5}\right) W$