- n2:1
- n:1
- 3√n:1
- √n:1
Solution: The correct answer is C.
$ By\text{ }mass\text{ }conservation\text{ }new\text{ }radius\text{ }R\text{ }is~ $
$ R={{n}^{1/3}}r $
$ ratio\text{ }of\text{ }energy\text{ }is:\,~\frac{nT\times 4\pi {{r}^{2}}}{T\times 4\pi {{R}^{2}}}={{n}^{1/3}}~:1 $