The correct option is D
Central maxima: Distance between the first dark fringes on either.
$=\frac{2 \lambda \mathrm{D}}{\mathrm{b}}=\frac{2 \times 600 \times 10^{-6} \times 2}{3 \times 10^{-3}} \mathrm{~m}$
$=2.4 \times 10^{-3} \mathrm{~m}$
$=2.4 \mathrm{~mm}$