A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)
A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)

The ball’s speed is 54 km/h.

The ball is deflected backwards to a total angle of 450 degrees.

The initial momentum of the ball is mucosӨ = (0.15 x 54 x 1000 x cos 22. 5)/3600

= 0.15 x 15 x 0.9239 along NO

The ball’s final momentum is mucos along ON.

2mucos = 2 x 0.15 x 15 x 0.9239 = 4.16 kg.m/s Impulse = change in momentum = mucos – (-mucos) = 2mucos = 2 x 0.15 x 15 x 0.9239 = 4.16 kg.m/s