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A bag contains \[\mathbf{3}\] white, \[\mathbf{5}\] black and \[\mathbf{2}\] red balls, all of the same shape and size. A ball is drawn from the bag without looking into it, find the probability that the ball drawn is: \[\left( \mathbf{i} \right)\]a black ball. \[\left( \mathbf{ii} \right)\] a red ball.
A bag contains \[\mathbf{3}\] white, \[\mathbf{5}\] black and \[\mathbf{2}\] red balls, all of the same shape and size. A ball is drawn from the bag without looking into it, find the probability that the ball drawn is: \[\left( \mathbf{i} \right)\]a black ball. \[\left( \mathbf{ii} \right)\] a red ball.
CBSE | Class 10 | Probability | Selina
A bag contains \[\mathbf{3}\] white, \[\mathbf{5}\] black and \[\mathbf{2}\] red balls, all of the same shape and size. A ball is drawn from the bag without looking into it, find the probability that the ball drawn is: \[\left( \mathbf{i} \right)\]a black ball. \[\left( \mathbf{ii} \right)\] a red ball.

Total number of balls \[=\text{ }3\text{ }+\text{ }5\text{ }+\text{ }2\text{ }=\text{ }10\]

So, the total number of possible outcomes \[=\text{ }10\]

\[\left( i \right)~\] There are \[5\] black balls

So, the number of favourable outcomes \[=\text{ }5\]

Thus, P(getting a black ball) \[=~\text{ }5/10\text{ }=\text{ }1/2\]

\[\left( ii \right)\] There are \[2\]red balls

So, the number of favourable outcomes \[=\text{ }2\]

Thus, P(getting a red ball) \[=~\text{ }2/10\text{ }=\text{ }1/5\]

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