A bag contains $8$ red, $6$ white and $4$ black ball. if A ball is drawn at random from the bag. Find the probability that the drawn ball is(iii) Neither white nor black

(iii)  Let E be event of getting neither a white nor a black ball

Therefore, No. of favorable outcomes $=18–6–4$

$=8$(Total balls – no. of white balls – no. of black balls)

Thus, Probability, P(E) = Number of favorable outcomes/ Total number of outcomes

P(E) $=8/18=4/9$