As we know that total number of balls $=8+6+4=18$
So, Total no. of possible outcomes $=18$
(i) Let E = Event of getting red or white ball
Now, No. of favorable outcomes $=14$($8$ red balls $+6$ white balls)
We know, Probability, P(E) = Number of favorable outcomes/ Total number of outcomes
P(E) $=14/18$
P(E) $=7/9$
(ii) Let E be Event of getting a black ball
So, Number of favorable outcomes $4=4$ ($4$ black balls)
P(E) $=4/18$
P(E) $=2/9$
Then,
$(\overset{\scriptscriptstyle\rightharpoonup}{E})$= Event of not getting a black ball
$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-P(E)$
$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-\frac{5}{9}$
$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=\frac{7}{9}$