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A bag contains $6$ red, $8$ black and $4$ white balls. A ball is drawn at random. What is the probability that the ball drawn is not black?

Given that A bag contains $6$ red, $8$ black and $4$ white balls and a ball is drawn at random

to find: Probability that the ball drawn is not black

so, Total number of balls $6+8+4=18$

therefore, Total number of black balls is $8$

Thus, the total number of balls which are not black is $18–8=10$

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Hence, the probability of drawing a ball which is not black $=10/18=5/9$