Given is a bag containing 6 red, 4 white and 8 blue balls.
By using the formula of probability, we get,
P (E) = favourable outcomes / total possible outcomes
As three balls are drawn, se we need to find the probability that one is red, one is white and one is blue.
Total number of outcomes for drawing 3 balls is ${}^{18}C_3$
$n (S) = {}^{18}C_3 = 816$
Let E be the event that one red, one white and one blue ball is drawn.
$n (E) = {}^6C_1{}^4C_1{}^8C_1 = 192$
P (E) = n (E) / n (S)
= 192 / 816
= 4/17