Given is a bag containing 6 red, 4 white and 8 blue balls.
By using the formula of probability we get,
P (E) = favourable outcomes / total possible outcomes
Two balls are drawn at random, so the total possible outcomes will be ${}^{18}C_3$
n (S) = 816
(i) Let E be the event of getting one red and two white balls
E = {(W) (W) (R)}
$n (E) = {}^6C_1{}^4C_2 = 36$
P (E) = n (E) / n (S)
= 36 / 816
= 3/68
(ii) Let E be the event of getting two blue and one red
E = {(B) (B) (R)}
$n (E) = {}^8C_2{}^6C_1 = 168$
P (E) = n (E) / n (S)
= 168 / 816
= 7/34