(a) If a weight W is placed at a distance of 250 cm from the support on the long arm, Find W.
(b) If a weight 5 kgf is kept to balance the rod, find its position.
(c) To which class of lever does it belong?
Solutions:
According to the question –
Total length of rod is 4 m = 400 cm
(a) We are given that the 18 kgf load is placed at 60 cm from the support and weight W kgf is placed at 250 cm from the support.
Using the principle of moments, we have –
18 × 60 = W × 250
Therefore, W = 4.32 kgf
(b) We have W = 5 kgf
In this case, the18 kgf weight is placed at 60 cm from the support.
Consider that the 5 kg of weight is placed at d cm from the support.
Using the principle of moments, we have –
18 × 60 = 5 × d
therefore, d = 216 cm from the support on the long arm
(c) It belongs to class I lever