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A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end and a load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.
A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end and a load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.
Class 10 | ICSE | Machines | Physics | Selina
A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end and a load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.

(a) If a weight W is placed at a distance of 250 cm from the support on the long arm, Find W.
(b) If a weight 5 kgf is kept to balance the rod, find its position.
(c) To which class of lever does it belong?

Solutions:

According to the question –

Total length of rod is 4 m = 400 cm

(a) We are given that the 18 kgf load is placed at 60 cm from the support and weight W kgf is placed at 250 cm from the support.

Using the principle of moments, we have –

18 × 60 = W × 250

Therefore, W = 4.32 kgf

(b) We have W = 5 kgf

In this case, the18 kgf weight is placed at 60 cm from the support.

Consider that the 5 kg of weight is placed at d cm from the support.

Using the principle of moments, we have –

18 × 60 = 5 × d

therefore, d = 216 cm from the support on the long arm

(c) It belongs to class I lever

i

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